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The math behind Michael Jordan’s legendary hang time - Andy Peterson and Zack Patterson

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    Michael Jordan once said,
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    "I don't know whether I'll fly or not.
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    I know that when I'm in the air
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    sometimes I feel like I don't ever
    have to come down."
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    But thanks to Isaac Newton,
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    we know that what goes up
    must eventually come down.
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    In fact, the human limit
    on a flat surface for hang time,
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    or the time from when your feet leave
    the ground to when they touch down again,
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    is only about one second,
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    and, yes, that even includes his airness,
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    whose infamous dunk
    from the free throw line
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    has been calculated at .92 seconds.
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    And, of course, gravity is what's making it
    so hard to stay in the air longer.
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    Earth's gravity pulls all nearby objects
    towards the planet's surface,
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    accelerating them
    at 9.8 meters per second squared.
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    As soon as you jump,
    gravity is already pulling you back down.
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    Using what we know about gravity,
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    we can derive a fairly simple equation
    that models hang time.
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    This equation states that the height
    of a falling object above a surface
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    is equal to the object's initial height
    from the surface plus its initial velocity
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    multiplied by how many seconds
    it's been in the air,
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    plus half of the
    gravitational acceleration
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    multiplied by the square of the number
    of seconds spent in the air.
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    Now we can use this equation to model
    MJ's free throw dunk.
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    Say MJ starts, as one does,
    at zero meters off the ground,
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    and jumps with an initial vertical
    velocity of 4.51 meters per second.
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    Let's see what happens if we model
    this equation on a coordinate grid.
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    Since the formula is quadratic,
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    the relationship between height
    and time spent in the air
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    has the shape of a parabola.
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    So what does it tell us about MJ's dunk?
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    Well, the parabola's vertex shows us
    his maximum height off the ground
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    at 1.038 meters,
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    and the X-intercepts tell us
    when he took off
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    and when he landed,
    with the difference being the hang time.
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    It looks like Earth's gravity
    makes it pretty hard
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    for even MJ to get some solid hang time.
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    But what if he were playing an away game
    somewhere else, somewhere far?
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    Well, the gravitational acceleration
    on our nearest planetary neighbor, Venus,
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    is 8.87 meters per second squared,
    pretty similar to Earth's.
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    If Michael jumped here with the same
    force as he did back on Earth,
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    he would be able to get more
    than a meter off the ground,
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    giving him a hang time
    of a little over one second.
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    The competition on Jupiter
    with its gravitational pull
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    of 24.92 meters per second squared
    would be much less entertaining.
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    Here, Michael wouldn't even
    get a half meter off the ground,
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    and would remain airborne
    a mere .41 seconds.
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    But a game on the moon
    would be quite spectacular.
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    MJ could take off from behind half court,
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    jumping over six meters high,
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    and his hang time of over
    five and half seconds,
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    would be long enough for anyone
    to believe he could fly.
Title:
The math behind Michael Jordan’s legendary hang time - Andy Peterson and Zack Patterson
Description:

View full lesson: http://ed.ted.com/lessons/the-math-behind-michael-jordan-s-legendary-hang-time-andy-peterson-and-zack-patterson

Michael Jordan’s legendary slam dunk from the free throw line has been calculated at 0.92 seconds of pure hang time. But how many seconds could Jordan have gotten were he doing the same jump on Mars? Or Jupiter? Andy Peterson and Zack Patterson share the math equation behind hang time.

Lesson by Andy Peterson and Zack Patterson, animation by Oxbow Creative.

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Video Language:
English
Team:
closed TED
Project:
TED-Ed
Duration:
03:46

English subtitles

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