[Script Info]
Title: 
[Events]
Format: Layer, Start, End, Style, Name, MarginL, MarginR, MarginV, Effect, Text
Dialogue: 0,0:00:00.28,0:00:06.26,Default,,0000,0000,0000,,Kita teruskan dgn bab akhir \Ndlm Geometri Koordinat.
Dialogue: 0,0:00:06.76,0:00:10.76,Default,,0000,0000,0000,,Kali ini mengenai Lokus.
Dialogue: 0,0:00:12.100,0:00:16.100,Default,,0000,0000,0000,,Cth soalan: Titik bergerak, P (x,y)
Dialogue: 0,0:00:17.75,0:00:21.50,Default,,0000,0000,0000,,bergerak pd jarak malar
Dialogue: 0,0:00:21.64,0:00:25.64,Default,,0000,0000,0000,,dari titik A dan B.
Dialogue: 0,0:00:27.44,0:00:31.44,Default,,0000,0000,0000,,Jika ditafsir kpd persamaan Matematik,
Dialogue: 0,0:00:32.50,0:00:36.50,Default,,0000,0000,0000,,PA = PB
Dialogue: 0,0:00:37.70,0:00:41.86,Default,,0000,0000,0000,,Jarak PA = jarak PB
Dialogue: 0,0:00:43.22,0:00:47.22,Default,,0000,0000,0000,,Sekarang kita guna formula jarak,
Dialogue: 0,0:00:50.72,0:00:56.10,Default,,0000,0000,0000,,x2 = x, x1 = -1,
Dialogue: 0,0:00:57.23,0:01:23.94,Default,,0000,0000,0000,,maka, PA: \N√ [(x - (-1))2 + (y - 1)2] =
Dialogue: 0,0:01:24.12,0:01:41.69,Default,,0000,0000,0000,,PB: \N√ [(x - 5)2 + (y - (-1))2]
Dialogue: 0,0:01:42.49,0:01:43.79,Default,,0000,0000,0000,,Jadi,\N
Dialogue: 0,0:01:43.95,0:02:03.80,Default,,0000,0000,0000,,√ [(x +1)2 + (y - 1)2] = √ [(x - 5)2 + (y +1)2]
Dialogue: 0,0:02:06.49,0:02:10.30,Default,,0000,0000,0000,,Bagaimana nak hapuskan kesemua √ ?
Dialogue: 0,0:02:11.24,0:02:15.24,Default,,0000,0000,0000,,Caranya dgn kuasa-dua kan \Npersamaan kiri dan kanan.
Dialogue: 0,0:02:16.68,0:02:19.52,Default,,0000,0000,0000,,Maka tiada lagi √ .
Dialogue: 0,0:02:19.65,0:02:34.28,Default,,0000,0000,0000,,(x + 1)2 + (y - 1)2 = (x-5)2 + (y + 1 )2
Dialogue: 0,0:02:34.41,0:02:38.41,Default,,0000,0000,0000,,Kembangkan persamaan ini.
Dialogue: 0,0:02:38.92,0:02:46.82,Default,,0000,0000,0000,,PA: \Nx2 + 2x + 1 + y2 - 2y + 1
Dialogue: 0,0:02:47.00,0:02:55.41,Default,,0000,0000,0000,,PB:\Nx2 - 10x + 25 + y2 + 2y + 1
Dialogue: 0,0:02:58.91,0:03:02.91,Default,,0000,0000,0000,,Sekarang, jadikan persamaan ini = 0
Dialogue: 0,0:03:03.06,0:03:06.52,Default,,0000,0000,0000,,Kumpulkan semua anu ke sebelah kiri.
Dialogue: 0,0:03:06.65,0:03:14.77,Default,,0000,0000,0000,,x2 & y2 ada di kedua-dua belah.
Dialogue: 0,0:03:14.82,0:03:17.59,Default,,0000,0000,0000,,Jadi ia boleh terus dihapuskan.
Dialogue: 0,0:03:17.81,0:03:48.76,Default,,0000,0000,0000,,Maka,\N2x - 2y + 2 +10x -25 -2y - 1= 0
Dialogue: 0,0:03:49.68,0:03:51.77,Default,,0000,0000,0000,,Ringkaskan persamaan ini.
Dialogue: 0,0:03:51.99,0:04:16.52,Default,,0000,0000,0000,,12x - 4y - 24 = 0
Dialogue: 0,0:04:16.72,0:04:19.25,Default,,0000,0000,0000,,÷ persamaan ini dgn 4
Dialogue: 0,0:04:19.46,0:04:25.12,Default,,0000,0000,0000,,3x - y - 6 = 0
Dialogue: 0,0:04:25.46,0:04:31.94,Default,,0000,0000,0000,,Inilah cara utk dapatkan persamaan Lokus.
Dialogue: 0,0:04:32.07,0:04:41.12,Default,,0000,0000,0000,,Anda cuma tafsirkan ayat \Nke dlm bentuk persamaan Matematik.