1 00:00:00,586 --> 00:00:02,054 PROBLEM: "Construct a circle 2 00:00:02,054 --> 00:00:03,538 circumscribing the triangle." 3 00:00:03,538 --> 00:00:06,906 So that would be a circle that touches the vertices 4 00:00:06,906 --> 00:00:09,595 the three vertices of this triangle. 5 00:00:09,595 --> 00:00:12,703 So we can construct it using a compass 6 00:00:12,703 --> 00:00:14,578 and a straight edge, or a virtual compass 7 00:00:14,578 --> 00:00:15,784 and a virtual straight edge. 8 00:00:15,784 --> 00:00:17,087 So what we want to do is to center the circle 9 00:00:17,087 --> 00:00:20,735 at the perpendicular bisectors of the sides. 10 00:00:20,735 --> 00:00:21,696 Or sometimes that's called 11 00:00:21,696 --> 00:00:24,824 the 'circumcenter' of this triangle. 12 00:00:24,824 --> 00:00:27,058 So let's do that. 13 00:00:27,058 --> 00:00:29,567 And so let's think about – 14 00:00:29,567 --> 00:00:32,781 Let's try to construct where the perpendicular 15 00:00:32,781 --> 00:00:36,052 bisectors of the sides are. 16 00:00:36,052 --> 00:00:38,827 So let me put a circle right over here whose radius 17 00:00:38,827 --> 00:00:41,330 is longer than this side right over here. 18 00:00:41,330 --> 00:00:45,563 Now let me get one that has the same size. 19 00:00:45,563 --> 00:00:46,988 So let me make it the same size 20 00:00:46,988 --> 00:00:49,261 as the one I just did. 21 00:00:49,261 --> 00:00:51,458 And let me put it right over here. 22 00:00:51,458 --> 00:00:53,949 And this allows us to construct 23 00:00:53,949 --> 00:00:58,267 a perpendicular bisector. 24 00:00:58,267 --> 00:01:02,215 If I go through that point and this point right over here, 25 00:01:02,215 --> 00:01:06,165 this bisects this side over here, 26 00:01:06,165 --> 00:01:08,079 and it's at a right angle. 27 00:01:08,079 --> 00:01:10,016 So now let's do that for the other sides. 28 00:01:10,016 --> 00:01:12,657 So if I move this over here, 29 00:01:12,657 --> 00:01:14,955 and I really just have to do it for one of the other sides, 30 00:01:14,955 --> 00:01:17,435 because the intersection of two lines 31 00:01:17,435 --> 00:01:19,100 is going to give me a point. 32 00:01:19,100 --> 00:01:20,069 So I can do it 33 00:01:20,069 --> 00:01:21,412 for this side right over here. 34 00:01:21,412 --> 00:01:24,155 Let me scroll down so that you can see a bit clearer. 35 00:01:24,155 --> 00:01:27,102 So let me add another straight edge right over here. 36 00:01:27,102 --> 00:01:29,395 so I'm going to go through that point, 37 00:01:29,411 --> 00:01:31,623 and I'm going to go through this point. 38 00:01:31,623 --> 00:01:38,106 So that's the perpendicular bisector of 39 00:01:38,106 --> 00:01:39,518 this side right over here. 40 00:01:39,518 --> 00:01:41,592 And now I could do the third sided 41 00:01:41,592 --> 00:01:43,458 and it should intersect at that point. 42 00:01:43,458 --> 00:01:45,493 I'm not being ultra, ultra-precise. 43 00:01:45,493 --> 00:01:46,222 But I'm close enough. 44 00:01:46,222 --> 00:01:48,224 And now I just have to center one of these circles. 45 00:01:48,224 --> 00:01:50,663 Let me move one of these away. 46 00:01:50,663 --> 00:01:52,881 So let me just get rid of this one. 47 00:01:52,881 --> 00:01:55,320 And now I just have to move this circle 48 00:01:55,320 --> 00:01:58,656 to the circumcenter and adjust its radius so that 49 00:01:58,656 --> 00:02:03,142 it gets pretty close to touching the three sides, 50 00:02:03,142 --> 00:02:06,033 the three vertices of this triangle. 51 00:02:06,033 --> 00:02:07,230 It doesn't have to be perfect. 52 00:02:07,230 --> 00:02:09,268 I think this exercise has some margin for error. 53 00:02:09,268 --> 00:02:12,145 But they really want to see that you've made 54 00:02:12,145 --> 00:02:15,516 an attempt at drawing the perpendicular bisectors 55 00:02:15,516 --> 00:02:18,092 of the sides, and to find the circumcenter, 56 00:02:18,092 --> 00:02:21,467 and then you put a circle right over there.