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Lecture 11: BONUS!

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    This is calculus in a single variable and
    I'm Robert Ghrist, professor of
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    mathematics and electrical and systems
    engineering, at the University of
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    Pennsylvania. We're about to begin lecture
    eleven, Bonus Material. What have we
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    looked at? In lecture eleven we considered
    the various rules for computing
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    derivatives. Linearity, product rule,
    chain rule. Other kinds of rules. Why
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    spend so much time focusing on the rules?
    One reason is they help with computations.
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    But another deeper reason is that there
    are structures in mathematics and related
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    areas that obey similar types of rules.
    And when we find them and recognize them,
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    we can come to a deeper understanding by
    knowing how calculus works. Let's look at
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    two specific examples. One example
    involves spaces or domains over which you
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    might do calculus. Here are some specific
    examples, one type of space might be a
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    interval or a line segment. Another might
    be a circular disk. One thing that's
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    interesting to talk about when you're
    looking at the geometry of spaces is the
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    boundary. And we're going to think of
    boundary as an operator, not unlike a
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    derivative. In fact, we're going to give
    it a symbol that is evocative of the
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    differentiation symbol, called the
    script-e, d, dow, for the boundary
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    operator. Now what is the boundary of an
    interval or a line segment? It consists
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    precisely of two end points. What is the
    boundary of a circular disc? It consists
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    precisely of those points that are on the
    boundary the circle. Now, observe how the
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    boundary behaves with respect to other
    structures on spaces. There's a type of
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    product called the Cartesian product that
    is somewhat familiar even if you've never
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    seen it formally before. We denote it by a
    times sign. For example, a rectangle,
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    solid, filled-in rectangle can be
    considered as the Cartesian product of two
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    intervals. A solid cylinder can be
    considered as a product of an interval
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    with a circular disc. I'm sure you
    recognize many other shapes as well that
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    can be similarly decomposed. Now, what
    happens when we take the boundary of a
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    product o f spaces? For a rectangle, what
    we get are four edges with those corners.
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    Now notice that this perimeter of the
    rectangle can be decomposed, into a union
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    of two pieces. The two edges on the side,
    and the two edges on the top. We can think
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    of that as the boundary of the first
    interval times the second union, the
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    boundary of the second interval times the
    first. Similarly with the solid cylinder,
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    if we look at the boundary of that, we can
    decompose it into a couple of pieces.
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    There's the left and right hand sides of
    the cylinder, the, the, the round disk
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    part, that can be thought of as the disk
    times the boundary of the interval. And
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    then there's that portion of the boundary
    of the cylinder that wraps around the
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    sides. That can be thought of as the
    interval cross the boundary, of the disk.
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    It is a general fact that the boundary of
    the product of two spaces, A times B, is
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    equal to the boundary of A times B union A
    times the boundary of B. And if you look
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    at that formula carefully, you'll see what
    looks just like a product rule. But with
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    different operations involved. And indeed,
    there's a close and deep connection
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    between the boundary operator, Dell, and
    the derivative operator D, that we know
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    and love. Let's consider another example,
    this time coming from lists and computer
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    science. Consider a list with five
    elements. I'm going to represent each
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    element abstractly by a variable, x, so
    that the list of five elements might
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    suggestively be called x to the fifth. Now
    consider the following operator, a
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    deletion operator, d, that acts by
    deleting one of the terms in the list.
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    What happens? Well, I could delete the
    first term, or I could have deleted the
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    second term, or the third term, or the
    fourth term or the fifth. In this setting
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    I get a list of four elements. Or another
    list of four elements or another or
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    another or another. And if we call those
    lists of four elements algebraically as X
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    to the fourth and if we represent the
    logical or as a formal addition, then what
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    do we have? We really have that the
    deletion operat or D applied to X to the
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    fifth equals five times X to the fourth.
    Now where have you seen something like
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    that before? It turns out that there's an
    entire calculus for lists. Let's look at a
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    simple example of how this works. Let us
    denote by x to the n a list of n elements.
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    What would x to the zero be? A list of
    zero elements. Oh, that would be an empty
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    list. And what should we call that
    mathematically? Let's call that one,
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    because x to the zero really ought to be
    one.
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    And now consider the set L of all finite
    lists. We'd like to know, what does L look
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    like, symbolically. Here's a statement
    that I think you'll agree is true. Any
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    list is either empty or it has a first
    entry. What does that translate to you,
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    algebraically? Any list means L, is,
    connotes an equal sign, empty. Oh, we've
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    seen what the empty list is, that's one.
    we've seen that OR, corresponds to a
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    formal addition. And what does it mean,
    for a list to have a first entry? That
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    means, you've got an X followed by some
    other finite list, or X times L. Now,
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    let's just take that algebraic equation
    and start manipulating it. Forget about
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    what these things mean grammatically, for
    the moment. If I move X, x L to the other
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    side, factor out L and divide through by
    1-X, then we'll get that L is equal to one
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    over one minus x. Now what does that mean?
    I've come up with an algebraic expression
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    for all finite lists and I recognize one
    over one minus X as the geometric series
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    one plus X plus X squared plus X cubed
    etcetera. One way to interpret that, is
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    that we have derived the fact. That the
    set of all finite lists consists of the
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    empty list, or a list of one element, or a
    list of two elements, or a list of three
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    elements, etc. That's a pretty remarkable
    derivation. It's using a type of calculus,
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    that is very different from what we're
    learning in this class but has some
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    strange similarities. And as you go on in
    your calculus education, you'll see that
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    calculus applies not just to, problems in
    physics or economics, but in all kinds of
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    fields and in all kinds of manners, which,
    a t first, might not have been so obvious.
Title:
Lecture 11: BONUS!
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